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This test applies the addition and product rules of combinatorics. Students count possible selections and arrangements, organise a solution systematically and avoid including duplicate outcomes.
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With order important and no repetition, arranging n elements gives n! possibilities and assigning r distinct roles gives n!/(n − r)!. An unordered pair gives n(n − 1)/2. A code with r positions, n symbols per position and repetition allowed gives nʳ.
For successive choices joined by “and”, multiply: shirt and trousers give a × b outfits. For disjoint alternatives joined by “or”, add: bus or train gives a + b choices.
Count all unrestricted arrangements. Count the forbidden arrangements by treating A and B as one block and allowing both orders inside it. Subtract forbidden arrangements from the total.
With order important and no repetition, arranging n elements gives n! possibilities and assigning r distinct roles gives n!/(n − r)!. An unordered pair gives n(n − 1)/2. A code with r positions, n symbols per position and repetition allowed gives nʳ.
With order important and no repetition, arranging n elements gives n! possibilities and assigning r distinct roles gives n!/(n − r)!. An unordered pair gives n(n − 1)/2. A code with r positions, n symbols per position and repetition allowed gives nʳ.
With order important and no repetition, arranging n elements gives n! possibilities and assigning r distinct roles gives n!/(n − r)!. An unordered pair gives n(n − 1)/2. A code with r positions, n symbols per position and repetition allowed gives nʳ.
With order important and no repetition, arranging n elements gives n! possibilities and assigning r distinct roles gives n!/(n − r)!. An unordered pair gives n(n − 1)/2. A code with r positions, n symbols per position and repetition allowed gives nʳ.
Count unordered pairs from the first group: swapping the pair does not create a new choice. Count choices for the second-group member separately. Both selections are required, so multiply their counts.
For successive choices joined by “and”, multiply: shirt and trousers give a × b outfits. For disjoint alternatives joined by “or”, add: bus or train gives a + b choices.
For successive choices joined by “and”, multiply: shirt and trousers give a × b outfits. For disjoint alternatives joined by “or”, add: bus or train gives a + b choices.
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https://www.catestia.com/en/mathematics/10th-grade/combinatorial-rules-test/97/