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Multiply and divide by two-digit numbers. Practise partial products, a zero in the quotient and remainders.
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Calculate 2012 × 44. Pay attention to the zero in the first number.
A zero inside the number does not change the place values of other digits. Keep digits aligned by place value, calculate both partial products and add them.
A student divided 9480 by 37 and wrote quotient 254 and remainder 82. The equality divisor × quotient + remainder = dividend is true, but the division is unfinished. Correct the result. Choose the pair: quotient; remainder.
The remainder must be smaller than the divisor. Find how many more times the divisor fits into the reported remainder. Add that number to the reported quotient and subtract the corresponding divisor product from the reported remainder. Check both requirements: divisor × quotient + remainder = dividend and 0 ≤ remainder < divisor.
The quotient of 5413 ÷ 20 is shown in the diagram. What is the remainder?
Multiply the divisor by the displayed quotient and subtract this product from the dividend. The remainder must be non-negative and smaller than the divisor.
The calculation is 809 × 52. Which second partial product is marked with a question mark?
The second partial product represents multiplication by tens: multiply the first number by the tens digit and by 10. Do not treat tens as units.
Use long division to divide 4680 by 20. There is no remainder.
Starting from the left, take the shortest dividend prefix at least as large as the divisor. Find a quotient digit, multiply, subtract and bring down the next digit. Repeat. Check: divisor × quotient = dividend.
Calculate 337 × 92 using long multiplication. Choose the product.
Multiply by the units digit and by the tens digit. Multiply the tens partial product by 10, then add the two partial products.
The calculation is 179 × 28. Which digit of the product is hidden by the question mark?
Add the displayed partial products with digits aligned by place value. Answer with the hidden digit only, not the whole product.
Divide 3090 by 15 using long division. The quotient contains a zero. There is no remainder.
When bringing down a digit gives a number smaller than the divisor, write 0 in the quotient. Then bring down another digit. Do not omit the zero, because it preserves the quotient place values.
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https://www.catestia.com/en/mathematics/5th-grade/long-multiplication-division-two-digit-test/213/