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Dynamic tasks on radius, diameter, circumference and the area of a circle and its parts, using π ≈ 3.14.
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In one complete revolution without slipping, a wheel travels its circumference, 2 × π × r. For n revolutions, distance = n × 2 × π × r. Use π ≈ 3.14.
A semicircle area is half the full circle area: S = π × r² ÷ 2. Use π ≈ 3.14. Express the result in cm².
Circle area is S = π × r². Multiply the radius by itself, then by 3.14. Use cm².
Circumference is C = 2 × π × r. Use 3.14 for π and multiply by twice the radius. This is a length in centimetres, not an area.
Area depends on the radius squared: S = πr². Multiplying the radius by k multiplies the area by k². For example, doubling the radius quadruples the area.
Circle area is S = π × r². Multiply the radius by itself, then by 3.14. Use cm².
The diameter passes through the centre and consists of two radii. Therefore d = 2 × r.
The circumference is the boundary of a circle and is measured in length units. The disk includes the interior as well as its boundary; its area is measured in square units.
Area depends on the radius squared: S = πr². Multiplying the radius by k multiplies the area by k². For example, doubling the radius quadruples the area.
A quarter-circle arc is one quarter of the circumference: l = 2 × π × r ÷ 4. Only the arc is requested, so do not add the lengths of the two radii.
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The circumference is the boundary of a circular region. Radius r joins the centre to the boundary, while diameter d = 2r passes through the centre. Circumference C = 2πr = πd and area A = πr².
Divide the full area by 2 or 4 for a half or quarter. Use the stated value of π. Circumference uses units of length, while area uses square units.
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https://www.catestia.com/en/mathematics/7th-grade/circumference-and-area-of-a-circle-test/58/