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Full Grade 9 test
Full Grade 9 mathematics test with mixed topics, dynamically selected questions and a choice of duration. Practise before an assessment or review the whole course at your own pace.
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Question 1out of 24
Question 2out of 24
First recognise a difference of squares in the numerator:
x2 − a2 = (x − a)(x + a).
After substituting this product, the numerators and denominators contain matching factors. Cancel x − b and x + a. The remaining factor is the final answer.
Even after the factors are cancelled, the restrictions from the original expression remain: its denominators cannot equal zero.
Question 3out of 24
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Question 9out of 24
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Question 15out of 24
To expand the brackets, multiply each term in the first pair of brackets by each term in the second:
(x − a)(x − b) = x2 − bx − ax + ab.
Combine the like terms:
(x − a)(x − b) = x2 − (a + b)x + ab.
- Multiply x · x.
- Combine the two terms containing x: −bx − ax.
- Multiply the constant terms: (−a)(−b) = ab.
Pay close attention to the signs. If a negative number appears in brackets, for example x − (−3), the expression is equal to x + 3.
Question 16out of 24
A point satisfies a system of equations only when its coordinates satisfy both equations.
- Substitute the point x-coordinate into the first equation and calculate x2.
- Compare the result with the point y-coordinate.
- Also check that the same y-coordinate satisfies the second equation.
If either equality is false, the point does not satisfy the system.
Question 17out of 24
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Question 19out of 24
In the trigonometric table, find the tan row and the stated angle column. Their intersection contains the answer.
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Question 22out of 24
The vertex form of a parabola is y = a(x − m)2 + n.
In this form, the vertex is V(m, n). Coefficient a does not change the vertex coordinates; it determines the opening direction and width.
Do not reverse the sign mentally: if the brackets contain x − (−m), the x-coordinate of the vertex is negative.
Question 23out of 24
Replace division by a fraction with multiplication by its reciprocal:
A/B ÷ C/D = A/B · D/C.
Then factor the difference of squares:
x2 − a2 = (x − a)(x + a).
Cancel matching factors. Remember that the divisor cannot equal zero, so in addition to denominator restrictions you must exclude the value that makes the numerator of the second fraction zero.
Question 24out of 24
The discriminant is an expression formed from the coefficients of a quadratic equation ax² + bx + c = 0. It helps determine the number of real solutions.
Formula: D = b² − 4ac.
- Identify the coefficients a, b and c, paying attention to their signs.
- Calculate b².
- Calculate 4ac and subtract it from b².
If D > 0, the equation has two real solutions; if D = 0, it has one; if D < 0, it has no real solutions.
Time left: 00:00:00
Full Grade 9 mathematics test
This complete Grade 9 mathematics test helps students review the main school topics in one mixed set of tasks. Questions are selected from different tests for this grade, so each attempt can be different.
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Choose a 15, 30, 45 or 60 minute test. A longer duration creates a larger task set covering calculation, word problems, geometry and other topics studied in the grade.
Practise before an assessment
A full grade test is useful for independent checking, revision before a class assessment or mathematics exam preparation. Work at your own pace, review the result and try again: dynamic questions help students learn methods instead of memorising previous answers.
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