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This test covers union, intersection and difference of sets and their representation with Venn diagrams. Absolute-value tasks develop interpretation as distance on a number line, equation solving and reasoning about real numbers.
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The midpoint coordinate is the average of the endpoint coordinates. Distance is the absolute value of the coordinate difference; a negative coordinate does not mean a negative distance.
The intersection A ∩ B contains elements in both sets. Count shared elements once in the union: |A ∪ B| = |A| + |B| − |A ∩ B|. Thus intersection size = |A| + |B| − |A ∪ B|, and |A \ B| = |A| − |A ∩ B|.
Convert the first inequality into a double inequality using distance. Intersect the two conditions. Check the inclusion of each endpoint separately.
Interpret the absolute values as distances to three points. Consider the position of x relative to those points and determine where the sum of distances is smallest.
Split |kx + b| = r into two equations: kx + b = r and kx + b = −r. Solve both equations and give both solutions.
The intersection A ∩ B contains elements in both sets. Count shared elements once in the union: |A ∪ B| = |A| + |B| − |A ∩ B|. Thus intersection size = |A| + |B| − |A ∪ B|, and |A \ B| = |A| − |A ∩ B|.
Use the identity √(u²) = |u|. If −a < x < a, then x − a < 0 and x + a > 0. Therefore |x − a| = a − x and |x + a| = x + a. Add the expressions to obtain the final numerical answer.
First calculate the expressions inside the two absolute-value signs separately. Then apply the definition of absolute value: a positive number remains unchanged, while a negative number is replaced by its positive opposite. Finally add the two non-negative values.
The equation |x − a| = d means that point x is d units away from point a on the number line. Therefore it normally has two solutions: x = a − d and x = a + d.
The intersection A ∩ B contains elements in both sets. Count shared elements once in the union: |A ∪ B| = |A| + |B| − |A ∩ B|. Thus intersection size = |A| + |B| − |A ∪ B|, and |A \ B| = |A| − |A ∩ B|.
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A set can be specified by listing its elements or by a defining property. The union A ∪ B contains elements in at least one set, the intersection A ∩ B those in both, and the difference A B those in A but not B.
The absolute value |x| is the distance from zero and is therefore non-negative. For a > 0, |x| = a gives x = a or x = −a. The inequality |x| < a describes points between −a and a, while |x| > a describes points outside. Include endpoints only when the inequality permits equality.
This test develops methods for rational, exponential and logarithmic inequalities. Students use the interval method, account for monotonicity of exponential or logarithmic functions and enforce all domain restrictions.
This test focuses on nth roots and powers with rational exponents. Students apply exponent laws, determine conditions under which expressions are defined and rationalise denominators.
Vector coordinates, linear combinations, parallelograms, parallel vectors, lengths and segment division.
This test covers exponential equations and their use in growth and decay models. Students rewrite expressions with a common base, solve equations and interpret percentage, compound and periodic change.
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https://www.catestia.com/en/mathematics/11th-grade/sets-and-absolute-value-test/99/