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This Grade 3 test consolidates division and its relationship with multiplication. Students calculate quotients, find missing values, check results by multiplication and solve simple situations involving equal sharing and grouping.
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You know the total amount and how many belong in one group. Divide the total by the size of one group.
For example, 24 objects in groups of 6 make 24 ÷ 6 = 4 groups. Check by multiplying the number of groups by the size of one group.
The divisor, the number after ÷, is missing. Find it by dividing the starting number by the result shown.
For example, for 48 ÷ ? = 6, the missing divisor is 48 ÷ 6 = 8. Check that 48 ÷ 8 = 6.
Divide the total number of biscuits by the number placed on each plate. The quotient is the number of plates needed. Check by multiplying the number of plates by the number of biscuits on each plate: this should give the total number of biscuits.
Use multiplication to work out a division. Find the number that, multiplied by the divisor, gives the starting number.
For example, 42 ÷ 7 = 6 because 6 × 7 = 42. The divisor is the number after ÷.
Equal sharing gives each child the same number of biscuits. Divide the total number of biscuits by the number of children.
Check: one child’s amount multiplied by the number of children must give all the biscuits.
The divisor, the number after ÷, is missing. Find it by dividing the starting number by the result shown.
For example, for 48 ÷ ? = 6, the missing divisor is 48 ÷ 6 = 8. Check that 48 ÷ 8 = 6.
You know the total amount and how many belong in one group. Divide the total by the size of one group.
For example, 24 objects in groups of 6 make 24 ÷ 6 = 4 groups. Check by multiplying the number of groups by the size of one group.
The divisor, the number after ÷, is missing. Find it by dividing the starting number by the result shown.
For example, for 48 ÷ ? = 6, the missing divisor is 48 ÷ 6 = 8. Check that 48 ÷ 8 = 6.
Use multiplication to work out a division. Find the number that, multiplied by the divisor, gives the starting number.
For example, 42 ÷ 7 = 6 because 6 × 7 = 42. The divisor is the number after ÷.
Sharing the cards equally gives every child the same amount. Divide the total number of cards by the number of children.
Multiplying one child’s amount by the number of children must give all the cards again.
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Division shows how a total can be shared equally or how many equal groups can be made. In 36 ÷ 6 = 6, 36 is the dividend, the first 6 is the divisor and the answer is the quotient. In a word problem, identify what each number represents.
For 42 ÷ 7, ask: “What number multiplied by 7 gives 42?” Since 7 × 6 = 42, the quotient is 6. To check, multiply the quotient by the divisor; the product must equal the dividend.
In a word problem, state whether the quotient represents the number of objects in each group or the number of groups.
This test explores multiplication and division rules involving 0, 1 and 10. Students also examine division of a number by itself, recognise that division by zero is undefined and justify the selected answer.
Full Grade 3 mathematics test with mixed topics, dynamically selected questions and a choice of duration. Practise before an assessment or review the whole course at your own pace.
This test consolidates multiplication facts from 5 to 9 and helps students notice relationships between products. Dynamic tasks improve speed, accuracy and the ability to use multiplication when solving division problems.
This test classifies triangles by their sides and angles. Students identify equilateral, isosceles and scalene triangles, distinguish acute, right and obtuse triangles and apply their defining properties.
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https://www.catestia.com/en/mathematics/3rd-grade/division-test/19/